(2x-5)(x^2+8)=0

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Solution for (2x-5)(x^2+8)=0 equation: 


Simplifying
(2x + -5)(x2 + 8) = 0

Reorder the terms:
(-5 + 2x)(x2 + 8) = 0

Reorder the terms:
(-5 + 2x)(8 + x2) = 0

Multiply (-5 + 2x) * (8 + x2)
(-5(8 + x2) + 2x * (8 + x2)) = 0
((8 * -5 + x2 * -5) + 2x * (8 + x2)) = 0
((-40 + -5x2) + 2x * (8 + x2)) = 0
(-40 + -5x2 + (8 * 2x + x2 * 2x)) = 0
(-40 + -5x2 + (16x + 2x3)) = 0

Reorder the terms:
(-40 + 16x + -5x2 + 2x3) = 0
(-40 + 16x + -5x2 + 2x3) = 0

Solving
-40 + 16x + -5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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